Chọn C
Ta có: \(y' = 3{x^2} + 6x - 9\) ; \(y' = 0 \Leftrightarrow \left[ \begin{array}{l}x = 1\\x = - 3\,\,\left( L \right)\end{array} \right.\). Khi đó\(y\left( 0 \right) = 1\), \(y\left( 1 \right) = - 4\), \(y\left( 4 \right) = 77\).
Vậy: \(M = 77\);\(\,m = - 4\).